Question

Find the first four terms of the sequence given by the following
a n=67+5(n-1), n=1, 2, 3...

Answer 1

The first four terms of the given sequence are 67, 72, 77, and 82.

Step-by-step explanation:

The given sequence is defined by the formula an = 67 + 5(n-1), where n represents the term number. To find the first four terms, we substitute n = 1, 2, 3, and 4 into the formula and calculate the corresponding values:

1. a1 = 67 + 5(1-1) = 67
2. a2 = 67 + 5(2-1) = 72
3. a3 = 67 + 5(3-1) = 77
4. a4 = 67 + 5(4-1) = 82

Therefore, the first four terms of the given sequence are 67, 72, 77, and 82.