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What is the change in the internal energy of a system that absorb 1,200 J of heat and that does 7,218 J of work on the surroundings at

constant pressure?

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Final answer:

The change in internal energy of a system that absorbs 1,200 J of heat and does 7,218 J of work on the surroundings is -6,018 J, indicating a decrease in internal energy.

Step-by-step explanation:

The change in the internal energy of a system can be found using the first law of thermodynamics, which states that the change in internal energy (∆U) of a system is equal to the heat (Q) added to the system minus the work (W) done by the system on the surroundings. The formula is ∆U = Q - W.

In the case given, the system absorbs 1,200 J of heat and performs 7,218 J of work on the surroundings.

Using the formula: ∆U = 1,200 J - 7,218 J = -6,018 J.

Therefore, the change in internal energy of the system is -6,018 J. The negative sign indicates that the internal energy of the system decreases.

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