Final Answer:
Each candy costs $0.40
Step-by-step explanation:
Sammy spent a total of $20.40 at the movie theater, which includes the cost of a movie ticket and candy. Let's denote the cost of the movie ticket as T and the cost of each candy bag as C. The given information can be expressed in the equation:
![\[ T + 3C = 20.40 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/5exfgeoiwgbmzvc0wgagm8xhq3ovtmhviu.png)
We know that Sammy bought a movie ticket for $10.20, so we substitute T with $10.20:
![\[ 10.20 + 3C = 20.40 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ed1bucmsjxbvhvft7906ct4usjnfobcz0a.png)
Now, solve for C by isolating the term with C:
![\[ 3C = 10.20 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/gq49lc8nrqk8ol8upqg85k04p3r7zi8ufr.png)
![\[ C = (10.20)/(3) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/aaf7867oz6go9lxl5pnbvbw3w493shp8s3.png)
![\[ C = 3.40 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/nvp1346nyyym25o1gmm9t89u77ak9jgvqg.png)
Therefore, each candy bag costs $3.40. However, the question asks for the cost of each candy, and we already know Sammy bought one candy bag for $3.40. To find the cost of each candy, we subtract the cost of the candy bag from the total amount spent on candy:
![\[ \text{Cost of each candy} = 3.40 - 3 = 0.40 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/38llirs9sx0h2d6hv7of19egr721mexd41.png)
So, each candy costs $0.40. In conclusion, Sammy spent $10.20 on the movie ticket and $10.20 on candy, with each candy costing $0.40.