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Identify the equation of the line perpendicular to y = 3x – 4 that runs through (-3,3).

User Stardt
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Final answer:

To find the equation of a line perpendicular to y = 3x - 4 that passes through (-3, 3), we can use the point-slope form of a line.

Step-by-step explanation:

To find the equation of a line perpendicular to y = 3x - 4 and passing through (-3, 3), we first need to determine the slope of the given line.

The slope of y = 3x - 4 is 3. Any line perpendicular to this will have a slope that is the negative reciprocal of 3, which is -1/3.

Using the point-slope form of a line, we can write the equation as y - y1 = m(x - x1), where (x1, y1) is the given point.

Substituting the values (-3, 3) and -1/3 for x1, y1, and m, respectively, we get:

y - 3 = -1/3(x - (-3))

Simplifying gives us:

y - 3 = -1/3(x + 3)

This is the equation of the line perpendicular to y = 3x - 4 that passes through the point (-3, 3).

User Ohe
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