Final answer:
The set B contains elements not present in set A which are 2, 3, 6.
Step-by-step explanation:
The set A AND B contains all outcomes that lie in both sets A and B, so A AND B = {14,16,18}. The set A OR B contains all outcomes that lie either of the sets A or B, so A OR B = {2, 4, 6, 8, 10, 12, 14, 15, 16, 17, 18, 19}.
From the given information, we know that AnB={1,4,5} and AuB={1,2,3,4,5,6}. Since the set A AND B contains all outcomes that are in both sets A and B, and AnB={1,4,5}, we can deduce that set A does not contain elements 2, 3, 6. Therefore, set B contains elements not present in set A which are 2, 3, 6.