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What is the calculation of the impulse on an object if a box is pushed 10 N for 2 sec?

A. 5 N-s
B. 12 N-s
C. 8 N-s
D. 20 N-s

User MGSoto
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1 Answer

5 votes

Final answer:

The impulse on an object when a 10 N force is applied for 2 seconds is 20 N-s, corresponding to answer choice D.

Step-by-step explanation:

The calculation of the impulse on an object when a force is applied can be found using the formula impulse = force × time. In this case, a force of 10 N is applied for 2 seconds, so the impulse would be calculated as follows:

The impulse on an object can be calculated by multiplying the force applied to the object by the time period for which the force is applied. In this case, the force applied to the box is 10 N and the time period is 2 seconds. Therefore, the impulse on the box is 10 N x 2 sec = 20 N-s (Option D).

Impulse = 10 N × 2 s = 20 N-sTherefore, the correct answer is D. 20 N-s.

User Michael McGriff
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