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Calculate the mass of AgCl that should be produced when an excess of AgNO3 is reacted with 500 mg of each of the following compounds. Mass of AgCl produced (g):

a. Co(NH_3)5ClCl_2
b. Co(NH_3)6Cl3
c. Both a and b
d. Neither a nor b

User Jim Webber
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1 Answer

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Final answer:

To calculate the mass of AgCl produced, we need to determine the moles of AgNO3 and use the stoichiometry of the reaction. Then we can convert the moles of AgCl to grams using the molar mass of AgCl.

Step-by-step explanation:

First, we need to calculate the number of moles of AgNO3 using its mass and molar mass. Assuming the molar mass of AgNO3 is 169.87 g/mol, we have:



Moles of AgNO3 = (mass of AgNO3) / (molar mass of AgNO3)



Next, we use the stoichiometry of the reaction to determine the moles of AgCl produced from the moles of AgNO3:



Moles of AgCl = Moles of AgNO3



Finally, we can convert the moles of AgCl to grams using the molar mass of AgCl:



Mass of AgCl = Moles of AgCl * (molar mass of AgCl)



By performing these calculations for each compound, we can determine the mass of AgCl produced for each scenario.

User Kyla
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