Question

A constant force of 25.0 N is applied, as shown, to a block which undergoes a displacement of 7.50 m to the right along a frictionless surface while the force acts. What is the work done by the force?

a) -162 J
b) -155 J
c) -125 J
d) 162 J
e) 155 J

Answer 1

The work done by a constant force on a block moving on a frictionless surface is calculated using the formula for work. Since the force is in the same direction as the displacement, the work done is the product of the force magnitude and displacement. In this case, the correct answer is 187.5 J, which is not listed in the provided options.

Step-by-step explanation:

The work done by a force is calculated using the formula W = F × d × cos(θ), where W is the work done, F is the magnitude of the force, d is the displacement, and θ is the angle between the force and the displacement. In this scenario, the force is applied in the same direction as the displacement, so the angle θ is 0 degrees and cos(0) = 1. Therefore, the work done can be calculated as:

W = 25.0 N × 7.50 m × cos(0)
W = 25.0 N × 7.50 m
W = 187.5 J

However, since this answer is not listed among the options you provided, there might have been a typo or misunderstanding in the question or the list of options given. The correct calculation shows that the work done by the force is 187.5 J, which is not listed as an option.