Question

For the following acid-base reaction, predict which side of the equilibrium is favored. The pKa of the neutral aromatic alcohol on the left side of the equilibrium is approximately:

a) 5
b) 8
c) 10
d) 12

Answer 1

The pKa of the neutral aromatic alcohol on the left side of the equilibrium is not provided in the options given.

Step-by-step explanation:

The pKa of the neutral aromatic alcohol on the left side of the equilibrium can be determined using the given information. The pKa of an alcoholic H is approximately 16, which is similar to the acidity of H₂O. Since the pKa of the neutral aromatic alcohol is not given, we can assume it is also around 16. Therefore, the correct answer is not provided in the options given (a) 5, (b) 8, (c) 10, (d) 12.