Final answer:
When the radius of an artery is constricted by a factor of 3, it results in a decrease in blood pressure. The decrease in blood pressure can be calculated using the equation: Delta P = 8nLQ / (pi * r^4).
Step-by-step explanation:
When the radius of an artery is constricted by a factor of 3, it results in a decrease in blood pressure. The decrease in blood pressure can be calculated using the equation:
Delta P = 8nLQ / (pi * r^4)
Where Delta P is the decrease in pressure, n is the viscosity of the blood, L is the length of the artery segment, Q is the flow rate, and r is the radius of the artery.
In this case, the radius is constricted by a factor of 3, so the new radius is 1/3 of the original radius. You can plug this new radius into the equation, along with the given flow rate, to calculate the decrease in blood pressure.
Given the initial flow velocity of 50 cm/sec, if we need to compute the change in blood pressure, we would rely on the blood flow rate changes and possibly apply the Bernoulli's equation, which relates the speed of a fluid to its pressure and potential energy, along with other hemodynamic equations that involve the flow rate, viscosity, and changes in radius to determine how these changes affect blood pressure.