Final answer:
Jeremy's weight at 1/8 the distance from the Earth's center would be 6.25 N.
Step-by-step explanation:
To calculate Jeremy's weight at 1/8 the distance from the Earth's center, we need to consider the gravitational force. The weight of an object is given by the equation w = mg, where w is the weight, m is the mass, and g is the acceleration due to gravity. On the surface of the Earth, the weight is 400 N.
Since the weight is directly proportional to the distance from the center of the Earth, we can use the inverse-square relationship. If Jeremy is at 1/8 the distance from the Earth's center, the gravitational force would be multiplied by (8^2) = 64. Therefore, Jeremy's weight at 1/8 the distance from the Earth's center would be 400 N x 1/64 = 6.25 N