Final answer:
The increased blood pressure at the patient's arm due to the elevation of the blood bag by 1.11 m is 11463.15 Pa. This is calculated using the hydrostatic pressure formula, which includes the density of blood, the acceleration due to gravity, and the elevation height.
Step-by-step explanation:
The question pertains to the difference in blood pressure when a bag of blood is raised 1.11 m above the level of a patient's arm. This is a physics problem that is going to utilize the principles of fluid statics, specifically the concept of hydrostatic pressure.
To find the additional pressure exerted on the patient's arm due to the elevated bag of blood, we use the hydrostatic pressure equation:
P = ρgh
Where:
- ρ (rho) is the density of the fluid (blood in this case), which is 1050 kg/m3
- g is the acceleration due to gravity, which is 9.81 m/s2
- h is the height the fluid is raised, which is 1.11 m
Substituting the given values, we get:
P = 1050 kg/m3 × 9.81 m/s2 × 1.11 m
P = 11463.15 kg·m/(s2·m2) = 11463.15 N/m2 = 11463.15 Pa
The blood pressure at the patient’s arm is 11463.15 Pa greater with the bag raised 1.11 m compared to if the bag were at the same height as the arm.