Final answer:
To solve the system of congruences x=2 (mod 3), x=1 (mod 4), and x = 3 (mod 5) using the method of back substitution, follow these steps: 1. Rewrite the first congruence, 2. Substitute the expression for x into the second congruence, 3. Solve the congruence, 4. Replace t in the expression for x, 5. Substitute x into the third congruence and solve, 6. Replace u in the expression for x, 7. Translate x back into a congruence to find the solution.
Step-by-step explanation:
- Rewrite the first congruence x=2 (mod 3) as x=3t+2.
- Substitute the expression for x from step 1 into the second congruence, giving 3t+2 = 1 (mod 4).
- Solve the congruence from step 2 to find t = 1 (mod 4), which implies t=4u+1 for some integer u.
- Replace t in the expression from step 1 with 4u+1 to obtain x = 12u+5.
- Substitute x=12u+5 into the third congruence x=3 (mod 5) and solve to find u = 4 (mod 5).
- Replace u in the expression from step 4 with 5v+4 to obtain the final solution x = 60v+53.
- Translate x=60v+53 back into a congruence to find the solution x = 53 (mod 60).