Question

a student dissolves 24.3 g Na2S2O3 in enough water to make a .302 M solution. How many mL solution did the student make

Answer 1

The student made 508 mL of the .302 M solution.

Step-by-step explanation:

To find the volume of the solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's calculate the moles of Na2S2O3:

Moles of Na2S2O3 = mass of Na2S2O3 / molar mass of Na2S2O3

Molar mass of Na2S2O3 = (2 x atomic mass of Na) + (1 x atomic mass of S) + (3 x atomic mass of O) = 2(22.99 g/mol) + 32.07 g/mol + 3(16.00 g/mol) = 158.10 g/mol

Substituting the given values, we get:

Moles of Na2S2O3 = 24.3 g / 158.10 g/mol = 0.1536 mol

Now, let's rearrange the formula to solve for volume:

Volume of solution = Moles of solute / Molarity

Substituting the given values:

Volume of solution = 0.1536 mol / 0.302 M = 0.508 L = 508 mL