51.9k views
4 votes
In a materials testing laboratory, a metal wire made from a new alloy is found to break when a tensile force of 93.5 N is applied perpendicular to each end. For related problem-solving tips and strategies, you may want to view a video tutor solution of

a) Mercantilism
b) Socialism
c) Laissez-faire liberalism
d) Absolutism

1 Answer

6 votes

Final answer:

The maximum load that can be lifted slowly at a constant speed by the rope is 4710 N. The maximum load that can be lifted by the rope with an acceleration of 4.00 m/s² is approximately 1177.5 kg.

Step-by-step explanation:

The maximum load that can be lifted slowly at a constant speed by the rope can be determined using the formula:

Maximum Load (force) = Tensile Stress x Cross-sectional Area

Given that the tensile stress is 6.00 x 10^6 N/m² and the cross-sectional area can be calculated using the formula for the area of a circle:

Area = π x (radius)²

Since the diameter is given as 1.0 mm, the radius will be 0.5 mm or 0.0005 m. Substituting these values into the formulas gives:

Area = π x (0.0005)² = 0.000785 m²

Maximum Load = 6.00 x 10^6 N/m² x 0.000785 m² = 4710 N

Therefore, the maximum load that can be lifted slowly at a constant speed by the rope is 4710 N.

To determine the maximum load that can be lifted by the rope with an acceleration of 4.00 m/s², we need to consider the force required to accelerate the load. This can be determined using Newton's second law:

Force = Mass x Acceleration

Since the acceleration is given as 4.00 m/s², we can calculate the mass of the load using the formula:

Mass = Force / Acceleration

Given that the force is 4710 N, we can substitute these values into the formula to find:

Mass = 4710 N / 4.00 m/s² = 1177.5 kg

Therefore, the maximum load that can be lifted by the rope with an acceleration of 4.00 m/s² is approximately 1177.5 kg.

User Fishcake
by
7.3k points