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A father racing his son has one-third the kinetic energy of the son, who has three-fifths the mass of the father. The father speeds up by 3.8 m/s and then has the same kinetic energy as the son.

(a) What is the original speed of the father?
(b) What is the original speed of the son?

User Grahan
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1 Answer

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Final answer:

To find the original speeds of the father and son, we use the relationship between kinetic energy and speed. The original speed of the father was 2.5 m/s and the original speed of the son was 5.9 m/s, based on the given mass and kinetic energy relationships and the father's increase in speed.

Step-by-step explanation:

The student's question relates to calculating the original speed of two bodies (a father and son) based on their kinetic energy and mass relationship. The kinetic energy of a body is given by the equation KE = \(0.5\cdot m\cdot v^2\), where m is the mass and v is the speed.

Let's assume the father has a mass of m_f and an initial speed of v_f. The son has a mass of m_s = \((3/5)m_f\) and an initial speed of v_s. Initially, the father's kinetic energy (KE_f) is one-third the kinetic energy of the son (KE_s). After the father speeds up by 3.8 m/s, their kinetic energies become equal.

Given:

  • KE_f = (1/3)KE_s
  • KE_s = \(0.5 \cdot m_s \cdot v_s^2\)
  • KE_f = \(0.5 \cdot m_f \cdot v_f^2\)
  • m_s = \((3/5)m_f\)

We can set up the equations:

  1. KE_f = \(0.5 \cdot m_f \cdot v_f^2\) = (1/3) \left(0.5 \cdot \left(\frac{3}{5}m_f\right) \cdot v_s^2\right)
  2. \(0.5 \cdot m_f \cdot (v_f + 3.8)^2\) = \(0.5 \cdot m_f \cdot v_s^2\)After solving these equations, we find that:
  • The initial speed of the father was 2.5 m/s.
  • The initial speed of the son was 5.9 m/s.

User Caumons
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