Question

A stone is tied to a 0.85-meter cord. It is swung in a circle at a constant rate of 6.0 m/s. What is the centripetal acceleration of the stone?

a.5.1 m/s 2
b.0.14 m/s 2
c.7.1 m/s 2
d.42 m/s 2

Answer 1

The centripetal acceleration of a stone tied to a 0.85-meter cord and swung in a circle at a constant rate of 6.0 m/s is approximately 42 m/s², calculated using the formula ac = v² / r.

Step-by-step explanation:

To calculate the centripetal acceleration (ac) of the stone, we use the formula:

ac = v² / r

where:

• v = linear velocity (6.0 m/s)
• r = radius of the circle (0.85 meters)

Plugging in the values:

ac = (6.0 m/s)² / 0.85 m

ac = 36 m²/s² / 0.85 m

ac ≈ 42.35 m/s²

Since we do not have an exact match in the options but 42 m/s² is the closest, the answer to the question 'What is the centripetal acceleration of the stone?' would be approximately 42 m/s² (Answer d).