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Water is boiled at 2000-m elevation where the standard atmospheric pressure is 79.5 kPa. It is boiled in a 25-cm internal diameter stainless steel pan on an electric range. If it is observed that the water level in the pan drops by 10.2 cm in 45 min, determine the rate of heat transfer to the pan. The properties of water at 79.5 kPa are Tsat = 93.3°C, hfg = 2273.9 kJ/kg, and v/= 0.001038 m³/kg.

The rate of heat transfer to the pan is ______KW.

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Final answer:

The rate of heat transfer to the pan is 2.59 kW.

Step-by-step explanation:

The rate of heat transfer to the pan can be calculated using the equation for heat transfer. The heat lost by the water is equal to the heat gained by the pan. Given that the water level in the pan drops by 10.2 cm in 45 min, we can calculate the mass of water evaporated using the volume of the pan. By using the properties of water at 79.5 kPa, we can find the heat transfer rate. The rate of heat transfer to the pan is 2.59 kW (kilowatts).

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