Question

A conducting loop of wire enclosing an area of 7.1 x 10⁻² m and resistance of 100Ω, Perpendicular to the plane of the loop is a magnetic field of strength 0.36 T

At what rate (in T/s) must this field change if the induced current in the loop is to be 0.28 A ?

Answer 1

To induce a current of 0.28 A in the loop, the magnetic field must change at a rate of ΔB/Δt = 0.28 / (7.1 x 10^-2 * t)

Step-by-step explanation:

To find the rate at which the magnetic field must change in order to induce a current of 0.28 A in the loop, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the emf induced in a loop is equal to the rate of change of magnetic flux through the loop. The magnetic flux is given by the product of the magnetic field strength and the area of the loop, so we can write the equation as emf = B * A * t, where B is the magnetic field strength, A is the area of the loop, and t is the time taken for the change in the magnetic field. Rearranging the equation to solve for the rate of change of the magnetic field, we get ΔB/Δt = emf / (A * t). Plugging in the given values of emf = 0.28 A, A = 7.1 x 10⁻² m², and solving for ΔB/Δt gives us the rate at which the magnetic field must change.