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A circular area with a radius of 6.70cm lies in the xy-plane.What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field with a magnitude of 0.240T in the + z -direction?

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Final answer:

Magnetic flux is calculated by the product of the magnetic field strength, the area of the circle, and the cosine of the angle between the field direction and normal to the surface. Here, the angle is 0 degrees due to the field being in the +z-direction and the surface in the xy-plane.

Step-by-step explanation:

The question asks for the magnitude of the magnetic flux through a circular area in the presence of a uniform magnetic field. The formula to find magnetic flux (Φ) is the product of the magnetic field strength (B), the area through which the field lines pass (A), and the cosine of the angle (θ) between the field direction and the normal to the surface, or Φ = B * A * cos(θ). In this case, since the magnetic field is in the +z-direction and the circle lies in the xy-plane, the angle is 0 degrees, which means cos(0) = 1. The area of a circle is π*r^2, so with a radius (r) of 6.70 cm (0.067 m), the area (A) = π*(0.067 m)^2.

To calculate the magnetic flux, you apply the values into the formula: Φ = (0.240 T) * (π*(0.067 m)^2)

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