Question

Review. As it passes over Grand Bahama Island, the eye of a hurricane is moving in a direction 60.08 north of west with a speed of 41.0 km/h. (a) What is the unit-vector expression for the velocity of the hurricane

Answer 1

Velocity = -20.45 i + 35.54 j km/h

Step-by-step explanation:

given data

speed v = 41.0 km/h

direction = 60.08 north of west

solution

first we get here Speed in west direction that is express as

Speed in west direction = v × cos(60.08) ..........................1

Speed in west direction = 41 × cos(60.08)

Speed in west direction = 20.45 km/h

now we get Speed in north direction that is

Speed in north direction = v × sin(60.08) ............................2

Speed in north direction = 41 × sin(60.08)

Speed in north direction = 35.54 km/h

so Velocity will be here

Velocity = -20.45 i + 35.54 j km/h