Final answer:
To convert 5 grams of ice at 0°C to water at the same temperature, 1667.75 joules of heat are required, calculated by multiplying the mass of ice by the heat of fusion of water (333.55 J/g).
Step-by-step explanation:
The amount of heat required to convert 5 grams of ice at 0°C to water at the same temperature can be calculated by using the heat of fusion for water, which is the amount of heat needed to melt a certain mass of ice without changing its temperature. The heat of fusion for water is 333.55 J/g. The formula used to calculate the heat needed for this phase change is Q = m × Lf, where Q is the heat absorbed, m is the mass of the ice, and Lf is the heat of fusion. For 5 grams of ice, this would be Q = 5 g × 333.55 J/g = 1667.75 joules.