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If n(A) = 63, n(B) = 18, and n(A n B) = 3, find n(A U B). Need Help? Read It 5. [0/0.58 Points]

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Final answer:

Using the formula n(A U B) = n(A) + n(B) - n(A n B), with n(A) = 63, n(B) = 18, and n(A n B) = 3, we find that n(A U B) = 78.

Step-by-step explanation:

To find the number of elements in the union of two sets, A U B, we can use the formula n(A U B) = n(A) + n(B) - n(A n B). The number of elements in set A, n(A), is 63. The number of elements in set B, n(B), is 18. The number of elements in the intersection of both sets A and B, n(A n B), is 3.

Now, we can substitute these values into the formula:

n(A U B) = 63 + 18 - 3 = 78

So, the number of elements in the union of sets A and B, or n(A U B), is 78.

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