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How many moles of H2O are present in a 59,502 gram sample of H2O?

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Final answer:

The number of moles of H2O in a 59,502 gram sample of water is calculated by dividing the mass of the sample by the molar mass of water (18.015 g/mol), resulting in 3,303.51 moles of H2O.

Step-by-step explanation:

To determine how many moles of H2O are present in a 59,502 gram sample of H2O, we use the molar mass of water as a conversion factor from mass to moles. The molar mass of water is calculated by adding the atomic masses of two hydrogen atoms (1.0079 + 1.0079) and one oxygen atom (15.999), which equals 18.015 g/mol. Therefore:

(59,502 grams H2O) × (1 mol H2O / 18.015 grams H2O) = Number of moles of H2O

To find the number of moles:

59,502 g ÷ 18.015 g/mol = 3,303.51 moles of H2O (rounded to two decimal places)

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