Final answer:
At equilibrium, the pressure potential of a cell with a solute potential of -0.35 kPa placed in pure water will become +0.35 kPa.
Step-by-step explanation:
A cell with a solute potential of -0.35 kPa placed in a solution of pure water will experience the movement of water into the cell until equilibrium is reached. At equilibrium, the water potential inside the cell (Ψtotal, cell) will equal the water potential of the pure water (Ψtotal, water) which is typically 0 kPa because pure water has a solute potential (Ψs) of 0 and a default pressure potential (Ψp) of 0. Therefore, at equilibrium, the pressure potential (Ψp) of the cell will be +0.35 kPa since the sum of pressure potential and solute potential must equal 0 kPa to match the water potential of the surrounding pure water.