Question

The gas in a balloon has a volume of 7.5 L at 100. kPa. The balloon is released into the atmosphere, and the gas in it expands to a volume of 11 L. Assuming a constant temperature, what is the pressure on the balloon at the new volume? What law did you use to solve? Make sure to show all work, for partial credit if your answer happens to be incorrect Equations: P1V1 = P2V2 P1/T1 = P2/T2 V1/T1 =V2/T2 P1V1/T1 =P2V2/T2.

Answer 1

Using Boyle's Law, which states that the product of pressure and volume of a gas is constant at a fixed temperature, the new pressure is found to be 68.18 kPa when the volume increases from 7.5 L to 11 L.

Step-by-step explanation:

To determine the new pressure on the balloon at the new volume, we use Boyle's Law, which states that for a given mass of an ideal gas at constant temperature, the product of pressure and volume is constant (P1V1 = P2V2). Here, P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume. Given that the initial pressure P1 is 100 kPa, and the initial volume V1 is 7.5 L, and the final volume V2 is 11 L, we can set up the equation:

P1V1 = P2V2

100 kPa * 7.5 L = P2 * 11 L

To find P2, we rearrange the equation:

P2 = (P1V1) / V2

P2 = (100 kPa * 7.5 L) / 11 L

P2 = 68.18 kPa

Therefore, the new pressure on the balloon at a volume of 11 L is 68.18 kPa.