100k views
4 votes
Find the standard deviation of the set of sample date 55,53,76,52,91

User Meligy
by
7.6k points

1 Answer

5 votes

Final answer:

To find the standard deviation of the sample data (55, 53, 76, 52, 91), calculate the mean, then find the deviations, square them, sum them, divide by n-1, and take the square root. The sample standard deviation is approximately 17.39.

Step-by-step explanation:

To find the standard deviation of the set of sample data (55, 53, 76, 52, 91), you would follow these steps:

  1. Calculate the mean (average) of the numbers.
  2. Subtract the mean from each number to find the deviation of each number from the mean.
  3. Square each of the deviations.
  4. Find the sum of the squared deviations.
  5. Divide this sum by the sample size minus one (which is the degrees of freedom for a sample standard deviation).
  6. Take the square root of the result from step 5 to get the sample standard deviation.

Here, the mean (step 1) is Σx/n = (55+53+76+52+91)/5 = 327/5 = 65.4.

Next, calculate the deviations (step 2), square them (step 3), and sum them up (step 4):
(55-65.4)^2 = 108.16
(53-65.4)^2 = 153.76
(76-65.4)^2 = 112.36
(52-65.4)^2 = 179.56
(91-65.4)^2 = 655.36
The sum of these values is 1209.2.

Divide by the degrees of freedom, which is n-1 (step 5). With five numbers, we have n-1 = 4 degrees of freedom, so 1209.2 / 4 = 302.3.

Finally, take the square root of 302.3 to get the sample standard deviation (step 6), which is approximately √302.3 = 17.39 when rounded to two decimal places.

User Stkvtflw
by
7.8k points