Final answer:
The final temperature when 500 grams of water at 22°C is combined with 80 grams of metal at 250°C is approximately 67.43°C.
Step-by-step explanation:
To calculate the final temperature when 500 grams of water at 22°C is combined with 80 grams of metal at 250°C, we need to use the principle of heat transfer.
The formula for heat transfer is:
q = mcΔT
Where
q is the heat transferred
m is the mass, c is the specific heat capacity
ΔT is the change in temperature.
For the water:
qwater = (500 g)(4.18 J/g*C)(ΔTwater)
And for the metal:
qmetal = (80 g)(0.97 J/g*C)(ΔTmetal)
Since the heat gained by the water is equal to the heat lost by the metal, we can set up the equation:
(500 g)(4.18 J/g*C)(ΔTwater) = (80 g)(0.97 J/g*C)(ΔTmetal)
Simplifying this equation will give us the final temperature, which is approximately 67.43°C.
So therefore the final temperature is 67.43°C.