Question

A wagon is being pulled across a wooden floor. The handle makes an angle of 60° with the wagon. A force of 75N is exerted on the handle. What is the component of the force parallel to the floor?

Answer 1

The component of the force parallel to the floor is 37.5N.

Step-by-step explanation:

To find the component of the force parallel to the floor, we need to calculate the parallel component of the force applied to the handle. In this case, the force applied to the handle is 75N and the angle between the handle and the wagon is 60°.

To calculate the component, we can use the formula:

Force parallel = Force applied * cos(angle)

Substituting the values, we have:

Force parallel = 75N * cos(60°) = 75N * 0.5 = 37.5N

Answer 2

The component of the force parallel to the floor when the handle makes a 60° angle with the wagon and a force of 75N is exerted is 37.5N. This is found using the cosine of the angle multiplied by the force.

Step-by-step explanation:

To calculate the component of the force parallel to the floor when a wagon is being pulled with a handle making an angle of 60° with the wagon, you use the cosine function. Given a force of 75N exerted, you can calculate the horizontal force (Fhorizontal) as follows:

Fhorizontal = F * cos(θ)

Where F is the force applied (75N) and θ is the angle the force makes with the horizontal (60°). Using this formula:

Fhorizontal = 75N * cos(60°) = 75N * 0.5 = 37.5N.

Therefore, the component of the force parallel to the floor is 37.5N.