Question

A grindstone of radius 2.50 m that is spinning with a constant angular speed of 4.80 rad/s. What is the magnitude of the centripetal acceleration (in m/s²) of a point on the rim of the grindstone?

Answer 1

The magnitude of the centripetal acceleration of a point on the rim of the grindstone is 55.104 m/s².

Step-by-step explanation:

The centripetal acceleration of a point on the rim of the grindstone can be calculated using the formula: a = r * ω², where a is the centripetal acceleration, r is the radius of the grindstone, and ω is the angular speed. Plugging in the values, we get:

a = (2.50 m) * (4.80 rad/s)² = 55.104 m/s²

So, the magnitude of the centripetal acceleration at a point on the rim of the grindstone is 55.104 m/s².