Question

A winch takes 11.5 seconds to lift a 1.23 kilogram piece of metal 1.85 meters vertically. The power supply for the winch is set at 12.5 Volts and it shows 1.15 Amperes of current being used. What is the efficiency, in percent, of the system?

Answer 1

To calculate the efficiency of the system, determine the useful power output and the power input. Calculate the useful power output by finding the work done to lift the metal and the power input by using the formula P = V * I. Divide the useful power output by the power input and multiply by 100 to get the efficiency in percent.

Step-by-step explanation:

To calculate the efficiency of the system, we need to determine the useful power output and the power input. The useful power output is the power used to lift the metal, and the power input is the power supplied by the power source.

First, let's calculate the useful power output. The formula for power is P = W / t, where P is power, W is work done, and t is time. The work done to lift the metal is equal to the weight of the metal multiplied by the distance lifted. The weight is mass multiplied by gravity, so W = (m * g) * h.

Now, let's calculate the power input. The formula for power is P = V * I, where P is power, V is voltage, and I is current. Plug in the given values to calculate the power input.

Finally, divide the useful power output by the power input and multiply by 100 to get the efficiency in percent.

The efficiency of the system is calculated as follows: Efficiency = (Useful Power Output / Power Input) * 100%.