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What is the polar form of -3+sqrt3i

User Michael Leaney
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2 Answers

7 votes
7 votes

Answer:

The answer is D!!

Explanation:

Right on edg 2022

User Narsereg
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16 votes
16 votes

Solution

For this case we have the following number given:


-3+\sqrt[]{3}i

We can see that x = -3 and y = - sqrt(3)

The angle is given by:


\arctan (\frac{-\sqrt[]{3}}{3})=-30=-(\pi)/(6)

The radius would be:


r=\sqrt[]{(3)^2+(-\sqrt[]{3})^2}=\sqrt[]{12}

And the polar form would be given by:


z=\sqrt[]{12}(\cos (-(\pi)/(6))+i\sin (-(\pi)/(6)))\text{ }

User Jkff
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