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Calculate the volume of water (in cm3) that overflows when a Pyrex beaker filled to the brim with 250 cm3 of water at 20 °C is heated to 60 °C. **Do not enter the units. Coefficients of Volume Expansion: Substance Coefficient x10-4 /°C. Water 2.1 Pyrex glass 0.09 **Do not enter the units in your final answer.

User JonathanZ
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Final answer:

The volume of water that overflows when a 250 cm³ Pyrex beaker is heated from 20 °C to 60 °C is 2.01 cm³, calculated using the coefficients of volume expansion for water and Pyrex.

Step-by-step explanation:

To calculate the volume of water that overflows when a Pyrex beaker filled with 250 cm³ of water at 20 °C is heated to 60 °C, we need to consider the coefficient of volume expansion (α) for both water and Pyrex. The formula for volume expansion is V = V_0(1 + α(T - T_0)), where V is the final volume, V_0 is the initial volume, α is the coefficient of volume expansion, and T - T_0 is the temperature change.

For water, V_water = 250 cm³(1 + 2.1 × 10⁻⁴/ °C × (60 °C - 20 °C)) = 250 cm³(1 + 2.1× 10⁻⁴ × 40) = 250 cm³(1 + 0.0084) = 250 cm³ × 1.0084 = 252.1 cm³.

Now, for Pyrex:

V_Pyrex = 250 cm³(1 + 0.09 × 10⁻⁴/ °C × (60 °C - 20 °C)) = 250 cm³(1 + 0.09 × 10⁻⁴ × 40) = 250 cm³(1 + 0.00036) = 250 cm³ × 1.00036 = 250.09 cm³.

The difference in the volume expansion of water and Pyrex gives the overflow volume:

V_overflow = V_water - V_Pyrex = 252.1 cm³ - 250.09 cm³ = 2.01 cm³.

Therefore, the volume of water that overflows is 2.01 cm³.

User Jake Feasel
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