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Janet, Li Na, and Katie have 68 beads altogether.Janet has 3 times as many beads as Li Na.Katie has 5 more beads than Janet.How many beads does Katie have?

User Ganeshja
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1 Answer

8 votes
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Step-by-step explanation:

Given;

We are told that Janet, Li Na and Katie all have a total of 68 beads.

We are also told that;

(i) Janet has 3 times as many beads as Li Na

(ii) Katie has 5 more beads than Janet.

Required;

We are required to find out how many beads Katie has.

Step-by-step solution;

From the conditions given, Janet has 3 times as many beads as Li Na. That means if Li has an y number of beads, Janet's would be times 3.

Therefore, if Li Na is L and Janet is J, then it means;


\begin{gathered} Li\text{ }Na=l \\ Janet=3l \end{gathered}

Also we are told that Katie has 5 more beads than Janet. That means, if Katie is K, then;


\begin{gathered} Janet=3l \\ Katie=3l+5 \end{gathered}

Bear in mind that they all have a total of 68 beads. Hence, we add up their beads as follows;


\begin{gathered} LiNa+Janet+Katie=68 \\ l+3l+3l+5=68 \end{gathered}
7l+5=68

Subtract 5 from both sides;


7l+5-5=68-5
7l=63

Divide both sides by 7;


(7l)/(7)=(63)/(7)
l=9

This means Li Na has 9 beads. If Katie's bead is given by the expression 3l + 5, then she will have;


\begin{gathered} Katie=3l+5 \\ Katie=3(9)+5 \\ Katie=18+5 \\ Katie=23 \end{gathered}

ANSWER:

Katie has 23 beads.

User Nilo Alan
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