Question

A student is performing a dilution in lab. They pipet 4.11 mL of 0.971 M FeSO4 into a test tube, then add 6.04 mL of water. What is the concentration of FeSO4 in the diluted solution?

a) 0.393 M
b) 0.661 M
c) 0.578 M
d) 1.43 M

Answer 1

The concentration of FeSO4 in the diluted solution is 0.393 M.

Step-by-step explanation:

To find the concentration of FeSO4 in the diluted solution, we need to calculate the moles of FeSO4 in the original solution and the new volume of the diluted solution.

Moles of FeSO4 = (volume of FeSO4 solution) * (concentration of FeSO4) = (4.11 mL / 1000 mL/L) * (0.971 M) = 0.00399 mol

Moles of FeSO4 in diluted solution = moles of FeSO4 in original solution = 0.00399 mol

Volume of diluted solution = volume of FeSO4 solution + volume of water = (4.11 mL / 1000 mL/L) + (6.04 mL / 1000 mL/L) = 0.01015 L

Concentration of FeSO4 in the diluted solution = moles of FeSO4 / volume of diluted solution = 0.00399 mol / 0.01015 L = 0.393 M