Question

What are the respective concentrations (M) of Cu+2 and Cl' afforded by dissolving 0.200 mol CuCl2 in water and

diluting to 345 mL?
A) 0.200 and 0.200
B) 0.580 and 1.16
C 0.200 and 0.400
D) 1.16 and 2.32
E 0.580 and 0.290

Answer 1

To determine the respective concentrations of Cu+2 and Cl- when dissolving 0.200 mol CuCl2 in water and diluting to 345 mL, we need to know the initial volume of the solution.

Step-by-step explanation:

To determine the respective concentrations of Cu+2 and Cl- when dissolving 0.200 mol CuCl2 in water and diluting to 345 mL, we can use the dilution equation C1V1 = C2V2. In this equation, C1 represents the initial concentration of the solution, V1 represents the initial volume of the solution, C2 represents the final concentration of the solution, and V2 represents the final volume of the solution.

Here, the initial concentration is 0.200 mol CuCl2, the initial volume is not provided, the final concentration of Cu+2 is unknown, the final concentration of Cl- is unknown, and the final volume is 345 mL.

To find the final concentrations, we need to know the initial volume of the solution. Without that information, it is not possible to calculate the respective concentrations of Cu+2 and Cl- afforded by dissolving 0.200 mol CuCl2 in water and diluting to 345 mL.