Question

Two baseball players hit 50 home runs combined last season. The first player hit 8 more home runs than twice the number of home runs the second player hit. How many home runs did each player hit?

Answer 1

The second player hit 14 home runs and the first player hit 36 home runs.

Step-by-step explanation:

Let's assume the number of home runs hit by the second player is x.

The first player hit 8 more home runs than twice the number of home runs hit by the second player. So, the number of home runs hit by the first player can be represented as 2x + 8.

Given that the combined home runs hit by both players is 50, we can set up an equation:

x + (2x + 8) = 50

Simplifying the equation, we get 3x + 8 = 50.

Subtracting 8 from both sides of the equation, we get 3x = 42.

Dividing both sides of the equation by 3, we get x = 14.

Therefore, the second player hit 14 home runs and the first player hit 2x + 8 = 2(14) + 8 = 28 + 8 = 36 home runs.