216k views
0 votes
An observer 70 meters south of a railroad crossing watches an eastbound train traveling at 60 meters per second. At how many meters per second is the train moving away from the observer 4 seconds after it passes through the intersection?

(A) 57.60
(B) 57.88
(C) 59.20
(D) 60.00
(E) 67.40

1 Answer

4 votes

Final answer:

The train is moving away from the observer at a speed of 60 meters per second.

Step-by-step explanation:

To determine the speed at which the train is moving away from the observer, we need to find the distance it has traveled away in 4 seconds. Since the train is moving directly east, its motion does not affect its distance from the observer, which remains constant.

Using the equation distance = speed x time, we can calculate the distance traveled by the train in 4 seconds as follows: distance = speed x time = 60 m/s x 4 s = 240 meters.

Therefore, the train is moving away from the observer at a speed of 240 meters in 4 seconds, which is equivalent to 60 meters per second. Therefore, the correct answer is (D) 60.00.

User Saddam
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories