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A 10 kg object experiences a horizontal force which causes it to accelerate at 5 m/s^2 , moving it a distance of 20 m, horizontally. How much work is done by the force? a) 200 Joules b) 1,000 Joules c) 2,000 Joules d) 0 Joules

User PGreen
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Final answer:

Using the formula for work, the force exerted on a 10 kg object that is accelerating at 5 m/s^2 over a distance of 20 m is used to calculate the work done. The force calculated using Newton's second law is 50 N, and the work done by the force is 1,000 Joules.

Step-by-step explanation:

The amount of work done by a force on an object is given by the formula W = F × d × cos(θ), where W is work, F is the magnitude of the force, d is the distance moved by the object, and θ is the angle between the force's direction and the direction of motion.

In this scenario, a 10 kg object experiences a horizontal force which causes it to accelerate at 5 m/s2, and since acceleration is provided, we can calculate the force using Newton's second law (F = ma), where m is mass and a is acceleration. With the force known and the distance moved by the object provided, we can then calculate the work done using the formula for work.

Given:
Mass (m) = 10 kg
Acceleration (a) = 5 m/s2
Distance (d) = 20 m

Force: F = ma = 10 kg × 5 m/s2 = 50 N
Work: W = F × d = 50 N × 20 m = 1000 Joules

Thus, the work done by the force is 1000 Joules, so the correct answer to the question is option (b) 1,000 Joules.

User Jensgram
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