Question

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds. Let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture.

Answer 1

Delaney would need 3.33 pounds of peanuts and 1.67 pounds of the 80% almond-20% peanut mixture to make the 5 lb nut mixture.

Step-by-step explanation:

We can set up a system of equations to solve this problem.

Let's start by setting up the equation for the total weight of the new nut mixture: p + m = 5

Next, let's set up the equation for the total weight of the peanuts in the new mixture: (0.60)p + (0.20)m = 5

We can solve this system of equations to find the values of p and m. Using substitution or elimination method, we can find that p = 3.33 pounds and m = 1.67 pounds.

Therefore, Delaney would need 3.33 pounds of peanuts and 1.67 pounds of the 80% almond-20% peanut mixture to make the 5 lb nut mixture.