Question

What is an equation of the line that passes through the point (3.-8)
and has slope -27?

Answer 1

The equation of the line that passes through the point (3, -8) with a slope of -27 is y = -27x + 73.

Step-by-step explanation:

The student has asked about the equation of a straight line that passes through a specific point and has a given slope. To find the equation of the line, we will use the point-slope form which is y - y1 = m(x - x1), where (x1, y1) is the point the line passes through and m is the slope. In this case, (x1, y1) is (3, -8) and the slope m is -27. Plugging these values into the point-slope form we get:

y - (-8) = -27(x - 3)

This simplifies to:

y + 8 = -27x + 81

Finally, isolating y, we get the equation of the line:

y = -27x + 73