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Andrea pushes a 16.7 kg toy car on a frictionless, horizontal surface. If the toy car is initially at rest, what is the speed of the toy car after she pushes it for 6.6 s with an acceleration of +4.98 m/s2?

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Final answer:

The final speed of the toy car after being pushed for 6.6 seconds with an acceleration of 4.98 m/s² is 32.868 m/s. This is calculated using the kinematic equation for final velocity.

Step-by-step explanation:

The student is asking how to calculate the speed of a toy car that is being pushed by Andrea on a frictionless, horizontal surface. Using the information given, we know the mass of the toy car is 16.7 kg, the car is initially at rest, and it is pushed with an acceleration of 4.98 m/s2 for 6.6 seconds.

To find the final speed, we can use the kinematic equation:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Since the car is initially at rest, u = 0. Plugging in the given values, we get:

v = 0 + (4.98 m/s2) × (6.6 s)

The final velocity of the toy car is v = 32.868 m/s.

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