Question

You are making an electric circuit with a battery providing 3.0 V, and two resistors of resistance of 2.0 Ohm and 8.0 Ohm connected in parallel to the battery. What is the current out of the battery in A? Keep at least two significant figures. No units are needed for the answer, input just a numerical value for the specified units.

Answer 1

The current out of the battery when two resistors of 2.0 Ohm and 8.0 Ohm are connected in parallel with a 3.0 V battery is 1.875 A, calculated using the equivalent resistance formula for parallel resistors and Ohm's law.

Step-by-step explanation:

To calculate the current out of the battery when two resistors of resistance 2.0 Ohm and 8.0 Ohm are connected in parallel, we can use Ohm's law and the formula for the equivalent resistance of parallel resistors. First, we need to find the equivalent resistance (Req) of the circuit which is given by the formula 1/Req = 1/R1 + 1/R2. Substituting the values, we get 1/Req = 1/2.0 + 1/8.0, solving which gives Req = 1.6 Ohm.

Now we can find the current (I) using Ohm's law, I = V/Req, where V is the battery voltage. Substituting the given values, I = 3.0 V / 1.6 Ohm, which equals 1.875 A. The current out of the battery is therefore 1.875 A to two significant figures.