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What is the molarity of a solution prepared by dissolving 10.7g Nal in 0.250L

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Final answer:

To calculate the molarity of the NaI solution, the moles of NaI are first determined by dividing the mass of NaI by its molar mass. The molarity is then calculated by dividing the moles of NaI by the volume of the solution in liters.

Step-by-step explanation:

The question asks for the calculation of the molarity of a sodium iodide (NaI) solution prepared by dissolving 10.7 grams of NaI in 0.250 liters of solution. To find the molarity, we first need to calculate the number of moles of NaI using its molar mass (149.89 g/mol). The formula is: moles of NaI = mass of NaI (in grams) / molar mass of NaI (in g/mol).

After calculating the moles of NaI, the molarity can be found using the formula: Molarity (M) = moles of solute / volume of solution in liters.

Calculation Steps:

Calculate the number of moles of NaI: moles NaI = 10.7 g / 149.89 g/mol.

Calculate the molarity: Molarity = moles NaI / 0.250 L.

By following these steps, the molarity of the NaI solution can be determined, which represents how many moles of solute are present in one liter of solution.

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