Final answer:
192Ir will produce 192Pt upon undergoing beta decay, as beta decay causes an increase in atomic number while the mass number remains the same.
Step-by-step explanation:
The nuclide that will produce 192Pt (Platinum-192) upon undergoing beta decay is 192Ir (Iridium-192). Beta decay involves the conversion of a neutron into a proton within the nucleus, accompanied by the emission of an electron (beta particle). During beta decay, the mass number (A) remains the same while the atomic number (Z) increases by one. Therefore, for a nuclide to decay into 192Pt, it must have the same mass number (192) and an atomic number one less than that of platinum (Z = 78), which is iridium (Z = 77).