Final answer:
The mass/volume percent concentration of a solution prepared by dissolving 72.5 g of NaOH in enough water to produce 850 mL of solution is 8.53%.
Step-by-step explanation:
To calculate the mass/volume percent concentration of a solution made by dissolving 72.5 g of sodium hydroxide (NaOH) in enough water to produce 850.0 mL of solution, we can use the formula for mass/volume percent concentration:
% m/v = (mass of solute in grams / volume of solution in mL) × 100%
Plugging in the values we have:
% m/v = (72.5 g / 850.0 mL) × 100% = 8.53%
Therefore, the mass/volume percent concentration of the NaOH solution is 8.53% to three significant figures.