Final answer:
The equation for the dissociation of CaCO3(s) into calcium ions and carbonate ions is CaCO3(s) → Ca²+(aq) + CO3²−(aq). The Ksp of calcium carbonate is 4.5 × 10−⁹. At equilibrium, there are three species present: Ca²+, CO3²−, and HCO3−.
Step-by-step explanation:
The equation for the dissociation of CaCO3(s) into calcium ions and carbonate ions is: CaCO3(s) → Ca²+ (aq) + CO3²−(aq). The equilibrium concentrations of each ion are equal to s, which represents the molar solubility of CaCO3. The Ksp of calcium carbonate is 4.5 × 10−⁹.
Using a pKa chart, we can find that carbonate acts as a base and forms bicarbonate ions when dissolved in water. Therefore, at equilibrium, we have Ca²+, CO3²−, and HCO3− ions present. These ions can be represented by three equations: CaCO3(s) → Ca²+ + CO3²−, CO3²− + H2O → HCO3− + OH−, and H2O → H+ + OH−.
To calculate the concentrations of all species, we can use the solubility product expression for calcium carbonate and the equilibrium expressions for the bicarbonate and hydroxide ions. We can also use mole balance equations and charge balance equation to derive the necessary equations.