Question

Calculate it on a document (Include full solution)

1. A particle with a charge of 2.0x10⁻⁶C is moving at 3x10⁶ m/s perpendicularly through a magnetic field with a magnitude of 0.5 N. What is the strength of the magnetic field?​

Answer 1

To find the strength of the magnetic field, we can use the formula for the magnetic force on a charged particle. In this problem, we are given the charge of the particle, its velocity, and the magnetic force. Since the particle is moving perpendicular to the magnetic field, we can rearrange the formula to solve for B.

Step-by-step explanation:

To find the strength of the magnetic field, we can use the formula for the magnetic force on a charged particle:

F = qvBsinθ

Where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

In this problem, we are given the charge of the particle (2.0x10⁻⁶C), its velocity (3x10⁶ m/s), and the magnetic force (0.5 N).

Since the particle is moving perpendicular to the magnetic field, sinθ = 1. Therefore, we can rearrange the formula to solve for B:

B = F / (qv)

Plugging in the given values, we get:

B = 0.5 N / (2.0x10⁻⁶C)(3x10⁶ m/s) = 8.3x10⁻⁵ T

Therefore, the strength of the magnetic field is 8.3x10⁻⁵ T.