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According to the general equation for conditional probability of P(A and B) = 1/6 and P(B) = 7/24, what is P(A|B)?

User Murena
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Final answer:

P(A|B) is the probability of A given B. Given P(A AND B) = 1/6 and P(B) = 7/24, the calculation of P(A|B) is straightforward using the given formula, resulting in a conditional probability of 4/7.

Step-by-step explanation:

The student asked for the conditional probability P(A|B) given P(A AND B) = 1/6 and P(B) = 7/24. To find P(A|B), we use the formula P(A|B) = P(A AND B) / P(B), assuming P(B) > 0. Substituting the given values into this formula, we get P(A|B) = (1/6) / (7/24).

By simplifying the fraction, we get P(A|B) = (1/6) * (24/7) = 4/7. Therefore, the probability of A occurring given that B has already occurred is 4/7.

User Druhin Bala
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