Question

Scores for an exam are normally distributed with a mean of 235 and a standard deviation of 52. What is the percentile rank of a raw score 287? The percentile rank of a raw score 287 =----------------

Answer 1

The percentile rank of a raw score 287 with a mean of 235 and a standard deviation of 52 is approximately 84%.

Step-by-step explanation:

To find the percentile rank of a raw score 287 in a normal distribution with a mean of 235 and a standard deviation of 52, we need to calculate its z-score first. The z-score formula is: z = (x - mean) / standard deviation. Plugging in the values, we get: z = (287 - 235) / 52 = 1. In a standard normal distribution, the percentile rank corresponding to a z-score of 1 is approximately 84%. Therefore, the percentile rank of a raw score 287 is approximately 84%.